How much heat must be removed from 500 grams of water at 0 degrees C to form ice at 0 degrees c?
To calculate the amount of heat that must be removed from water at 0 degrees Celsius to form ice at 0 degrees Celsius, we need to use the equation:
Q = m * L
Where:
Q is the heat energy (in Joules)
m is the mass of the substance (in grams)
L is the specific latent heat of fusion (in J/g)
For water, the specific latent heat of fusion is 334 J/g.
Given:
Mass of water (m) = 500 grams
Specific latent heat of fusion (L) = 334 J/g
Substituting the given values into the equation:
Q = 500 grams * 334 J/g
Q = 167,000 Joules
Therefore, 167,000 Joules of heat must be removed from 500 grams of water at 0 degrees Celsius to form ice at 0 degrees Celsius.
To calculate the heat that must be removed from water to form ice at 0 degrees Celsius, we need to consider the specific heat capacity and the heat of fusion of water.
The process involves two steps:
1. Cooling the water from 0 degrees Celsius to its freezing point.
2. Freezing the water into ice at 0 degrees Celsius.
Step 1: Cooling the water
The specific heat capacity of water is 4.184 Joules per gram per degree Celsius (J/g°C). This means it takes 4.184 Joules of energy to raise 1 gram of water by 1 degree Celsius.
Given that we have 500 grams of water at 0 degrees Celsius, we can calculate the heat required to cool it to its freezing point, which is also 0 degrees Celsius.
Heat Q1 = Mass (m) × Specific heat capacity (c) × Change in temperature (ΔT)
= 500 g × 4.184 J/g°C × (0°C - 0°C)
= 0 Joules
Step 2: Freezing the water into ice
The heat of fusion of water is 334 Joules per gram (J/g). This value represents the amount of heat required to convert 1 gram of water at its freezing point into ice at the same temperature.
Since we are freezing 500 grams of water, we can calculate the heat required.
Heat Q2 = Mass (m) × Heat of fusion (ΔHf)
= 500 g × 334 J/g
= 167,000 Joules
Therefore, the total amount of heat that must be removed from 500 grams of water at 0 degrees Celsius to form ice at 0 degrees Celsius is 167,000 Joules.