wile e coyote pushes a 1500n rock toward the edge of a cliff with the road runner below. he gives a rock acceleration of .8m/s^2. what is the net force of the rcok?
m=1500/9.8 kg
F=ma =0.8•1500/9.8= …(N)
To find the net force on the rock, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a): F = m * a.
In this case, we are given the acceleration of the rock (a) as 0.8 m/s^2, but we need to determine the mass (m) in order to calculate the net force.
To find the mass of the rock, we can use the formula for weight (W) which is the product of mass (m) and acceleration due to gravity (g): W = m * g. The weight of the rock is given as 1500 N.
Rearranging the formula, we have m = W / g, where g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth).
So, the mass of the rock is m = 1500 N / 9.8 m/s^2 = 153.06 kg (rounded to two decimal places).
Now, we can calculate the net force (F) using Newton's second law: F = m * a.
F = 153.06 kg * 0.8 m/s^2 = 122.45 N (rounded to two decimal places).
Therefore, the net force exerted on the rock is approximately 122.45 N.