How many calories will take to convert 5 grams of 90C degree water to 0 C degree?
To calculate the calories required to change the temperature of a substance, we can use the equation:
Q = mcΔT
Where:
Q represents the amount of heat energy transferred (in calories),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in calories/gram degrees Celsius), and
ΔT is the change in temperature (in degrees Celsius).
In this case, we have:
m = 5 grams (mass of water)
c = 1 calorie/gram °C (specific heat capacity of water)
ΔT = (0 °C - 90 °C) = -90 °C (change in temperature)
Plugging these values into the formula:
Q = (5 grams) * (1 calorie/gram °C) * (-90 °C)
Q = -450 calories
The negative sign indicates that heat energy is being removed or transferred out of the system (the water is cooling down). Therefore, it would take 450 calories to convert 5 grams of 90 °C water to 0 °C.