How long does it take an automobile traveling in the left lane of a highway at 65.0 km/h to overtake (become even with) another car that is traveling in the right lane at 40.0 km/h when the cars' front bumpers are initially 80 m apart?
Divide the initial separation distance by the relative velocity.
80 m/(105,000 m/h) = 0.000762 h = 0.457 min = 2.74 seconds
where did u get 105,000 m/h from?
He got the 105,000 by adding the Initial Velocities together.
Barry Bonds hits a home run so that the baseball just clears
the top row of bleachers, 21.0 m high, located 130 m from
home plate. The ball is hit at an angle of 35.0° to the horizontal,
and air resistance is negligible. Find (a) the initial
speed of the ball, (b) the time at which the ball reaches the
cheap seats, and (c) the velocity components and the speed
of the ball when it passes over the top row. Assume the ball
is hit at a height of 1.00 m above the ground.
To find out how long it takes for the automobile in the left lane to overtake the car in the right lane, we can first calculate their relative speed:
Relative speed = Speed of the left lane car - Speed of the right lane car
Relative speed = 65.0 km/h - 40.0 km/h = 25.0 km/h
Now, we need to convert the relative speed to meters per second (m/s):
Relative speed = 25.0 km/h = (25.0 km/h) * (1000 m/km) * (1 h/3600 s)
= 25000 m/3600 s
≈ 6.94 m/s
Next, we can calculate the time it takes for the cars to close the initial gap of 80 m:
Time = Distance / Relative speed
Time = 80 m / 6.94 m/s
Time ≈ 11.52 seconds
Therefore, it takes approximately 11.52 seconds for the automobile in the left lane to overtake the car in the right lane when their front bumpers are initially 80 m apart, assuming their speeds remain constant.