Janet jumps off a high diving platform with

a horizontal velocity of 2.11 m/s and lands in
the water 2.6 s later.
How high is the platform? The acceleration
of gravity is 9.8 m/s2 .

a: 9.8

t: 2.6
v: 2.11
d: ?
d=vt+1/2at
d=(2.11)(2.6)+2(9.8)(2.6)
d=ANSWER

To find the height of the platform, we can use the equation of motion for vertical motion:

h = ut + (1/2)at^2

Where:
h = height of the platform (what we are trying to find)
u = initial vertical velocity (0 since Janet jumps off horizontally)
t = time taken (2.6 seconds)
a = acceleration due to gravity (-9.8 m/s^2, since it is acting downward)

Substituting the given values into the equation, we get:

h = 0 * 2.6 + (1/2) * (-9.8) * (2.6)^2

Simplifying the equation, we have:

h = 0 + (-4.9) * (2.6)^2

h = -4.9 * (6.76)

h = -33.124

Since height cannot be negative, we take the absolute value:

h = 33.124 meters

Therefore, the height of the platform is approximately 33.124 meters.

To calculate the height of the platform, we can use the equations of motion. In this case, we are given the horizontal velocity, the time of flight, and the acceleration due to gravity.

First, let's break down the problem into horizontal and vertical components. Since there is no acceleration in the horizontal direction, the horizontal velocity remains constant throughout the motion. Janet's initial horizontal velocity is 2.11 m/s.

In the vertical direction, we need to determine the height of the platform. We can use the formula:

h = (1/2) * g * t^2

where:
h is the height of the platform,
g is the acceleration due to gravity (9.8 m/s^2),
t is the time of flight (2.6 s).

Substituting the given values into the equation, we have:

h = (1/2) * 9.8 m/s^2 * (2.6 s)^2
= (1/2) * 9.8 m/s^2 * 6.76 s^2
= 33.9744 m

Therefore, the height of the platform is approximately 33.97 meters.