A certain 0.92 kg object will reach terminal velocity after 0.75 seconds. What is the speed of its terminal velocity and what is the force from air resistance at this speed? (Assume it would would accelerate at 9.81 m/s^2 until it reaches terminal velocity.)

To find the speed of the terminal velocity, you can use the equation:

v = gt

where v is the terminal velocity, g is the acceleration due to gravity (9.81 m/s^2), and t is the time it takes to reach terminal velocity (0.75 seconds).

Substituting the values, we get:

v = (9.81 m/s^2) * (0.75 s)
v = 7.35 m/s

Therefore, the speed of the object's terminal velocity is 7.35 m/s.

To find the force from air resistance at this speed, you can use the equation:

F = 0.5 * ρ * v^2 * A * Cd

where F is the force of air resistance, ρ is the density of the medium (air) (approximately 1.2 kg/m^3), v is the velocity of the object, A is the cross-sectional area of the object perpendicular to the direction of motion, and Cd is the drag coefficient.

Since we know the speed of terminal velocity (7.35 m/s), we can substitute the values:

F = 0.5 * (1.2 kg/m^3) * (7.35 m/s)^2 * A * Cd

However, we need additional information to calculate the force of air resistance accurately, specifically the cross-sectional area of the object (A) and the drag coefficient (Cd). These values depend on the shape and orientation of the object in motion.

Please provide the cross-sectional area and drag coefficient of the object in order to calculate the force of air resistance accurately.