A 14.0 g sample of Krypton has a temperature of 25C at 625mm Hg. What is the volume, in Milliliters, of the krypton?
Use PV = nRT. Remember V = L and T in kelvin. P in atm. Solve for V in L and convert to mL.
To find the volume of krypton, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
First, we need to convert the temperature from Celsius to Kelvin. The equation to convert Celsius to Kelvin is: K = °C + 273.15. Thus, the temperature in Kelvin is:
T = 25°C + 273.15 = 298.15 K.
Next, we need to rearrange the ideal gas law equation to solve for volume (V):
V = (nRT) / P.
To find the number of moles (n), we need to divide the given mass of krypton (14.0 g) by its molar mass. The molar mass of krypton (Kr) is approximately 83.80 g/mol.
n = mass / molar mass = 14.0 g / 83.80 g/mol = 0.167 mol.
The gas constant (R) is 0.0821 L·atm/(K·mol). However, we are given the pressure in mm Hg. So we need to convert the pressure to atmospheres (atm) since the gas constant has units in atm. There are 760 mm Hg in 1 atm.
P = 625 mm Hg / 760 mm Hg/atm = 0.822 atm.
Now we can substitute the values into the equation to find the volume:
V = (nRT) / P = (0.167 mol)(0.0821 L·atm/(K·mol))(298.15 K) / 0.822 atm.
By performing the calculation, we find:
V ≈ 6.04 L.
However, the question asks for the volume in milliliters (mL). Since 1 L is equal to 1000 mL, we can convert the volume from liters to milliliters by multiplying by 1000:
V ≈ 6.04 L × 1000 mL/L ≈ 6040 mL.
Therefore, the volume of the krypton sample is approximately 6040 mL.