if rock A is dropped from a cliff and rock B is thrown downward off the cliff, which of the two has a greater velocity?

Rock A

V^2 = Vo^2 + 2g*h.
V^2 = 0 + 2g*h
V = Sqrt(2g*h).

Rock B
V^2 = Vo^2 + 2g*h.
V = Sqrt(Vo^2+2g*h).

The Eq shows that rock B has the highest
final velocity.

To determine which rock has a greater velocity, we need to consider their initial conditions and the effect of gravity on their motion.

First, let's understand the initial conditions:
- Rock A is simply dropped from the cliff, meaning it starts with zero initial velocity.
- Rock B is thrown downward off the cliff, indicating it has an initial velocity in the downward direction.

Next, let's examine how gravity affects their motion:
- Both rocks are subject to the same gravitational force since they are on Earth.
- Gravity accelerates objects downward at a constant rate, which is approximately 9.8 meters per second squared (m/s^2).

Since Rock B has an initial velocity in the downward direction, it will continue to accelerate due to gravity. On the other hand, Rock A has no initial velocity, so it will only accelerate due to gravity.

Considering these factors, Rock B, which is thrown downward, has a greater velocity than Rock A as it has both an initial velocity and acceleration from gravity.