A capacitor has a charge of 5 µC when charged by a potential difference of 1.5 V. What is the capacitance of the capacitor?
3.3x10^-6 F
3.3x10^6 F
7.5x10^-6 F
0.3x10^6 F
I would think the answer is 3.3X10^F, or choice B
To find the capacitance of a capacitor, we can use the formula C = Q/V, where C represents the capacitance, Q represents the charge on the capacitor, and V represents the potential difference across the capacitor.
In this case, the charge Q is given as 5 µC (microcoulombs) and the potential difference V is given as 1.5 V. Plugging these values into the formula, we get:
C = 5 µC / 1.5 V
To simplify this calculation, we need to convert the charge from microcoulombs to coulombs by dividing by 1,000,000:
C = 5 * 10^-6 C / 1.5 V
Now, we can divide the charge by the potential difference to find the capacitance:
C = (5 * 10^-6 C) / 1.5 V
Simplifying this expression, we get:
C = 3.33 * 10^-6 F
Therefore, the capacitance of the capacitor is approximately 3.33x10^-6 F, which corresponds to choice C.