My numerator is 10 less than my denominator. I am equal to 3/5
do it the same way I just showed in the previous one
Let me know what you got
Can you please help me? I need to understand this problem. Thanks a lot
denominator ----x
numerator ------ x-10
(x-10)/x = 3/5
cross-multiply
5x-50 = 3x
2x = 50
x = 25
fraction is 15/25 which would reduce to 3/5
Thank You:)
To find the values of the numerator and the denominator, we can set up an equation based on the information given. Let's use "x" to represent the denominator.
According to the problem, the numerator (which is 10 less) can be expressed as x - 10. And, the fraction is equal to 3/5.
So, the equation becomes:
(x - 10)/x = 3/5
To solve this equation, we can cross-multiply:
5(x - 10) = 3x
Now, distribute the 5 on the left side:
5x - 50 = 3x
Next, move all terms involving x to one side:
5x - 3x = 50
Combine like terms:
2x = 50
Finally, solve for x by dividing both sides of the equation by 2:
x = 50/2
x = 25
So, the denominator is 25. Now we can substitute this value back into the numerator expression:
Numerator = x - 10 = 25 - 10 = 15
Therefore, the numerator is 15 and the denominator is 25.