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Calc Please Help
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 14, 2010 
calc
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
Calc. Limits
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
calculus
State which of the conditions are applicable to the graph of y = f(x). (Select all that apply.) lim x→infinity f(x) = −infinity lim x→a+ f(x) = L lim x→infinity f(x) = L f is continuous on [0, a] lim x→infinity f(x) = 0
asked by Lyric on September 23, 2011 
Math
Find the limit if it exists. lim 1/(x2) = infinity x→2+ lim 1/(x2) = negative infinity x→2 lim 1/(x2) = Does not exist x→2 lim (3x+2) = infinity x→∞ lim 999/(x^3) = 0 x→∞ Can someone check to make sure that I am
asked by David on May 19, 2016 
calculus  ratio test
infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity)  [(e^n+1)/((n+1)!)] * [(n!)/(e^n)]  = lim (n>infinity) 
asked by COFFEE on July 30, 2007 
Calculus  ratio test
infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity)  [(e^n+1)/((n+1)!)] * [(n!)/(e^n)]  = lim (n>infinity) 
asked by COFFEE on July 29, 2007 
calculus  interval of convergence
infinity of the summation n=0: ((n+2)/(10^n))*((x5)^n) .. my work so far. i used the ratio test = lim (n>infinity)  [((n+3)/(10^(n+1)))*((x5)^(n+1))] / [((n+2)/(10^n))*((x5)^n)]  .. now my question is: was it ok for me to
asked by COFFEE on July 30, 2007 
calculus  interval of convergence
infinity of the summation n=0: ((n+2)/(10^n))*((x5)^n) .. my work so far. i used the ratio test = lim (n>infinity)  [((n+3)/(10^(n+1)))*((x5)^(n+1))] / [((n+2)/(10^n))*((x5)^n)]  .. now my question is: was it ok for me to
asked by COFFEE on July 30, 2007 
Calculus
Find the horizontal asymptote of f(x)=e^x  x lim x>infinity (e^x)x= infinity when it's going towards infinity, shouldn't it equal to negative infinity, since 0infinity =  infinity lim x> infinity (e^x)x= infinity
asked by sh on December 9, 2010