Bonnie and Clyde are sliding 500 bank safe across the floor to their getaway car. The safe slides with a constant speed if Clyde pushes from behind with 385 of force while Bonnie pulls forward on a rope with 300 of force.What is the safe's coefficient of kinetic friction on the bank floor
F1+F2=F(fr)=μ•m•g
μ=(F1+F2)/m•g
To find the coefficient of kinetic friction (μ) on the bank floor, we need to consider the forces acting on the safe.
First, let's calculate the net force acting on the safe. The net force is equal to the difference between the force applied by Clyde and the force applied by Bonnie:
Net force = 385 N - 300 N
Net force = 85 N
Since the safe slides at a constant speed, we know that the net force is balanced by the force of kinetic friction.
The force of kinetic friction can be found using the equation:
Force of kinetic friction (Fk) = μ × Normal force
Where the Normal force is the force exerted by the floor perpendicular to the safe's motion. In this case, the Normal force is equal to the weight of the safe.
To calculate the weight of the safe, we can use the equation:
Weight (W) = mass × gravity
Assuming the mass of the safe is 500 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we have:
Weight (W) = 500 kg × 9.8 m/s^2
Weight (W) = 4900 N
Now we can substitute the weight into the equation for the force of kinetic friction:
85 N = μ × 4900 N
To find the coefficient of kinetic friction (μ), rearrange the equation:
μ = (Net force) / (Normal force)
μ = 85 N / 4900 N
Simplifying the equation gives:
μ ≈ 0.017
Therefore, the coefficient of kinetic friction on the bank floor is approximately 0.017.