Three blocks are in contact with each other

on a frictionless horizontal surface. A 696 N
horizontal force is applied to the block with
mass of 4.7 kg as shown in the figure below.
The acceleration of gravity is 9.8 m/s
2
.
4.7 kg 5.5 kg 7.1 kg
F
a) What is the net force on the block with
mass 4.7 kg?
Answer in units of N
011 (part 2 of 5) 10.0 points
b) What is the resultant force on the block
with mass 5.5 kg?
Answer in units of N
012 (part 3 of 5) 10.0 points
c) What is the resultant force on the block
with mass 7.1 kg?
Answer in units of N
013 (part 4 of 5) 10.0 points
d) What is the magnitude of the force between
the block with mass 5.5 kg and 7.1 kg?
Answer in units of N
014 (part 5 of 5) 10.0 points
e) What is the magnitude of the force between
the block with mass 4.7 kg and 5.5 kg?

To find the net force on each block and the magnitude of the force between the blocks, we need to consider the forces acting on the system.

a) The net force on the block with a mass of 4.7 kg can be found by using Newton's second law of motion. The formula is:

Net force = mass * acceleration

Since the block is on a frictionless surface, the only horizontal force acting on it is the applied force of 696 N. Therefore, the net force on the block is 696 N.

b) The resultant force on the block with a mass of 5.5 kg can be found by similarly using Newton's second law of motion:

Net force = mass * acceleration

Since the three blocks are in contact with each other and there is no friction, they will experience the same acceleration. Therefore, the resultant force on the block with a mass of 5.5 kg is also 696 N.

c) Again, using Newton's second law of motion, the resultant force on the block with a mass of 7.1 kg can be found:

Net force = mass * acceleration

Since the three blocks are in contact with each other and there is no friction, they will all experience the same acceleration. Therefore, the resultant force on the block with a mass of 7.1 kg is also 696 N.

d) The magnitude of the force between the block with a mass of 5.5 kg and the block with a mass of 7.1 kg can be found by using Newton's third law of motion. According to this law, every action has an equal and opposite reaction. Therefore, the force between the two blocks will be equal in magnitude but opposite in direction to the force applied to the 5.5 kg block. So, the magnitude of this force is also 696 N.

e) Finally, the magnitude of the force between the block with a mass of 4.7 kg and the block with a mass of 5.5 kg can be found by using Newton's third law of motion. Again, this force will be equal in magnitude but opposite in direction to the force applied to the 5.5 kg block. So, the magnitude of this force is also 696 N.

In summary:

a) Net force on the block with mass 4.7 kg = 696 N
b) Resultant force on the block with mass 5.5 kg = 696 N
c) Resultant force on the block with mass 7.1 kg = 696 N
d) Magnitude of the force between the block with mass 5.5 kg and 7.1 kg = 696 N
e) Magnitude of the force between the block with mass 4.7 kg and 5.5 kg = 696 N