In a TV set, an electron beam moves with
horizontal velocity of 4.5 × 10
7 m/s across the
cathode ray tube and strikes the screen, 48 cm
away.
The acceleration of gravity is 9.8 m/s
2
.
How far does the electron beam fall while
traversing this distance?
Answer in units of m
but how.
h=1/2 g t^2 where t=distance/velocity
To find the distance that the electron beam falls while traversing the given distance, we need to determine the time it takes for the electron beam to reach the screen. By using the horizontal velocity and the horizontal distance, we can calculate the time taken using the equation:
time = distance / velocity
Given that the horizontal velocity of the electron beam is 4.5 × 10^7 m/s and the horizontal distance is 48 cm (which is 0.48 m), we can substitute these values into the equation:
time = 0.48 m / 4.5 × 10^7 m/s
Calculating this will give us the time taken by the electron beam to reach the screen.
Once we have the time, we can calculate the vertical distance the electron beam falls using the following formula:
distance = 0.5 * acceleration * time^2
Here, the acceleration is the acceleration due to gravity, which is 9.8 m/s^2. We have already found the time in the previous step. By substituting these values into the equation, we can determine the vertical distance that the electron beam falls while traversing the given distance.
Using these steps, you can calculate the answer to the question.