The equation for the decomposition of silver oxide is 2(Ag2)o yields 4Ag +o2. Set up ratio to calculate the number of oxygen molecules released when 1 gram of silver oxide is broken down. There are 2.6 x 10 to 21 power molecules in 1 gram of silver oxide.
I know that it is a 2 to 1 ratio. I divided 2.6 x 10 to 21 power by 3 to get 8.66666... To 21 power. Is this wrong and why? I don't understand and my math teacher told me it was 1.3 x 10 to 21 power.
Please help me understand this
i re did your math and i got the exact same answer and even i still dont get it, also what grade are you in because im in 8th and if this is something from a higher grade, its on my teacher for doing this to us
I don't know i have been searching this doesn't help
g,g,
To calculate the number of oxygen molecules released when 1 gram of silver oxide decomposes, you are correct that we need to use the ratio from the balanced equation. In this case, the ratio is 2 moles of Ag2O to 1 mole of O2.
First, convert the mass of silver oxide into moles using the molar mass. The molar mass of Ag2O is calculated as follows:
2 (atomic mass of Ag) + 1 (atomic mass of O) = 2(107.87 g/mol) + 16.00 g/mol = 231.74 g/mol
Divide the mass of silver oxide (1 gram) by its molar mass (231.74 g/mol) to get the number of moles:
1 g / 231.74 g/mol ≈ 0.00431 moles of Ag2O
Next, use the ratio of 2 moles of Ag2O to 1 mole of O2 to calculate the number of moles of O2:
0.00431 moles of Ag2O × (1 mole of O2 / 2 moles of Ag2O) = 0.002155 moles of O2
Now, to convert moles to molecules, we use Avogadro's number, which is approximately 6.022 x 10^23 molecules per mole.
Multiply the number of moles of O2 by Avogadro's number to get the number of oxygen molecules:
0.002155 moles of O2 × 6.022 x 10^23 molecules/mole ≈ 1.3 x 10^21 molecules of O2
So, according to the calculations, the correct answer is approximately 1.3 x 10^21 oxygen molecules.
It seems like your initial calculation divided the number of molecules by 3, which might have been a mistake. Additionally, the result you obtained, 8.66666... x 10^21, is much higher than the value you got from your math teacher. Make sure to double-check your calculations and follow the steps outlined above for an accurate answer.