(20-r)^(1/2)= r
assuming you want to solve for r, square both sides to get
20-r = r^2
r^2 + r - 20 = 0
(r+5)(r-4) = 0
and it's all downhill from there.
Just remember: √25 = 5, not -5
Thank you!
To solve the equation (20-r)^(1/2) = r, we can follow these steps:
Step 1: Square both sides of the equation to eliminate the square root:
[(20 - r)^(1/2)]^2 = r^2
Step 2: Simplify by applying the power rule:
20 - r = r^2
Step 3: Rearrange the equation to get all terms on one side:
r^2 + r - 20 = 0
Step 4: Factorize the quadratic equation:
(r + 5)(r - 4) = 0
Step 5: Set each factor equal to zero and solve the resulting equations:
r + 5 = 0 or r - 4 = 0
For r + 5 = 0:
r = -5
For r - 4 = 0:
r = 4
Therefore, the solutions to the equation (20-r)^(1/2) = r are r = -5 and r = 4.
To find the value of r in the given equation, we can solve it step by step.
(20 - r)^(1/2) = r
Step 1: Square both sides of the equation to eliminate the square root:
[(20 - r)^(1/2)]^2 = r^2
Simplifying the left side of the equation:
(20 - r) = r^2
Step 2: Rearrange the equation in standard form:
r^2 + r - 20 = 0
Step 3: Factor the quadratic equation:
(r + 5)(r - 4) = 0
Step 4: Set each factor equal to zero and solve for r:
r + 5 = 0 or r - 4 = 0
For r + 5 = 0, subtract 5 from both sides:
r = -5
For r - 4 = 0, add 4 to both sides:
r = 4
Thus, the equation has two solutions: r = -5 and r = 4.