calculus
test the series for convergence or divergence.
the sum from n=1 to infinity of ((1)^n*e^n)/(n^3)
I said it converges because the derivative of (1/n^3) is decreasing
asked by
laura

Hi:
The series is alternating of the form(a_n)*(1)^n, where a_n = e^n/n^3. Because limit (n>inf)[a_n] not= 0 (a_n>inf as n>inf}, the series diverges.
Regards,
Rich B.
posted by rich
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