sally and susan had an equal amount of oney each. after sally spent $15 and susan spent $24, the ratio of sally's money to susan's money was 4:3. how much money did each girl have at first?

After they spent the money of $15 and $24 respectively, Sally has $x+9 and Susan has $x. Which is at a ratio of 4:3

(x+9)/x=4/3
4x=3x+27
x=27
So after spending the money, Sally has $36 and Susan has $27.
How much did they have to start with? Add $15 to Sally and $24 to Susan.
36+15=51
27+24=51
They had $51 each to start with.

24-15=9

4:3 multiply with 9 = 36:27
36+15= 51
27+24=51
Both have $51 at first

it hurts my brain

To solve this problem, we can set up an equation using the given information. Let's assume that Sally and Susan each had x dollars initially.

After Sally spent $15, she would have (x - 15) dollars left.

After Susan spent $24, she would have (x - 24) dollars left.

According to the given ratio, (x - 15) / (x - 24) = 4 / 3.

To solve the equation, we can cross-multiply:

3 * (x - 15) = 4 * (x - 24)
3x - 45 = 4x - 96

Next, we can simplify the equation:

3x - 4x = -96 + 45
-x = -51

To isolate x, we divide both sides of the equation by -1:

x = 51

Therefore, each girl initially had $51.

Noresponce

No answers. It's just cheating

$24 - $15 = $9.00.

They had the same amount left.But Susan
spent $9 more. Theefore, Susan had $9
more to begin with:

Sally had $X.
Susan had $(X+9).

(X+9)/X = 4/3.
4x = 3x + 27
X = $27.
X+9 = 27+9 = $36.