Reiny you helped me with this logarithm yesterday: How did you write it out as
log2 ( √A / B^3 )
Laws of logarithms
combine, write as a single logarithm
Need help on this question please, Im stuck, don't know where to go abouts from here: I did it on paint and uploaded it onto this website because I don't know how to do the subscript numbers, so it probably wouldnt really have made any sense.
h t t p : //imageshack . us/scaled/landing/560/maththing . png
Pre-Calculus - Reiny, Wednesday, October 17, 2012 at 8:54am
worked for me
your answer is correct, you might also write it as
log2 ( √A / B^3 )
A½ is √A
To simplify the expression log2 (√A / B^3), we can use the laws of logarithms. Let's break it down step by step:
1. Start with the expression log2 (√A / B^3).
2. According to the quotient rule of logarithms, we can rewrite it as log2 (√A) - log2 (B^3).
3. Using the power rule of logarithms, we can simplify log2 (√A) as 1/2 * log2 (A). So our expression becomes 1/2 * log2 (A) - log2 (B^3).
4. Applying the power rule again, we can rewrite log2 (B^3) as 3 * log2 (B).
5. Putting it all together, our simplified expression is 1/2 * log2 (A) - 3 * log2 (B).
So, log2 (√A / B^3) can be written as 1/2 * log2 (A) - 3 * log2 (B).