Two forces are the only forces acting on a
2.8 kg object which moves with an accelera-
tion of 2.5 m/s2 in the positive y direction.
One of the forces acts in the positive x direc-
tion and has a magnitude of 12 N.
What is the magnitude of the other force
f2?
Answer in units
ma=F1+F2
F2=ma-F1=2.8•2.5 -12 =-5 N (in -x-direction)
F1+F2 = M*a = 2.8*2.5i = 7i.
12+F2 = 7i, F2 =-12 + 7i=13.9 N[30.3o] N. of W.
To determine the magnitude of the other force, we first need to understand the forces acting on the object and then apply Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given information:
Mass of the object (m) = 2.8 kg
Acceleration of the object (a) = 2.5 m/s^2
Magnitude of one of the forces (F1) = 12 N
Since the object is moving in the positive y direction, the only force acting in the x direction is F1. Therefore, the net force in the x direction is F1. In the y direction, the net force is responsible for the acceleration of the object.
Let's calculate the net force in the y direction:
F_net y = m * a
F_net y = 2.8 kg * 2.5 m/s^2
F_net y = 7 N
Now, we know that the net force in the y direction is equal to the sum of the magnitudes of the individual forces in the y direction. Since there is only one force in the y direction (F2), we can conclude that the magnitude of F2 is equal to the net force in the y direction:
|F2| = |F_net y|
|F2| = 7 N
Therefore, the magnitude of the other force (F2) is 7 N.