Jessie’s average grade in Algebra for the first two terms is 73.5. What grade must he get in the third term to have an average of 75?

(73.5 + 73.5 + x )/3 = 75

Solve for x

17x*3 =75

To find the grade Jessie must get in the third term to have an average of 75, we need to first determine his total grade for the first two terms. Let's denote the grade in the third term as T.

Since the average grade is calculated by summing all the grades and dividing by the number of terms, we can set up the equation:

(73.5 * 2 + T) / 3 = 75

To solve this equation, we will multiply both sides by 3 to eliminate the denominator:

73.5 * 2 + T = 75 * 3

Now, simplify the equation:

147 + T = 225

To isolate T, subtract 147 from both sides:

T = 225 - 147

T = 78

Therefore, Jessie must get a grade of 78 in the third term to have an average of 75.