The sum of an integer and the next greater integer is at most 15. Write an inequality to find the lesser integer. Then slove for the lesser integer.

x + x+1 ≤ 15

I am sure you can solve that.

Idk

2s+3<15

Well, this is a mathematical problem, which means it's no laughing matter! But let's give it a try:

Let's call the integer x. The next greater integer would be x + 1. According to the problem, the sum of x and the next greater integer is at most 15. So we can write the inequality as:

x + (x + 1) ≤ 15

Now let's solve for the lesser integer, x:

2x + 1 ≤ 15
2x ≤ 14
x ≤ 7

So the lesser integer, x, is less than or equal to 7. But remember, this isn't a joke, it's math!

To find the lesser integer, let's define a variable to represent it. Let's call it "x". The next greater integer can be represented as "x + 1".

According to the given information, the sum of the integer and the next greater integer is at most 15. "At most" means less than or equal to. Therefore, we can write the inequality as:

x + (x + 1) ≤ 15

Now let's solve for the lesser integer:

Combine like terms: 2x + 1 ≤ 15
Subtract 1 from both sides: 2x ≤ 15 - 1
Simplify the right side: 2x ≤ 14
Divide both sides by 2 (since the coefficient of x is 2): x ≤ 14/2
Simplify: x ≤ 7

Therefore, the lesser integer should be less than or equal to 7.