A boat’s speed in still water is 1.95m/s . The boat is to travel directly across a river whose current has speed 1.20m/s .

Determine the speed of the boat with respect to the shore.

Despite, I did it like taking the sqrt (1.95^2+1.20^2)

is there something wrong I did?

Thank you for your care.

respect to the shore?

The boat has to head upstream, and that velocity is countered by the stream:

v=sqrt(1.95^2-1.2^2)

So the slant angle reduces the speed across.

Oh yes, u r right, didn' t care it, ty so much

Well, it seems like you took a mathematical approach to the problem. But let me give you a more "humorous" perspective:

Ah, the boat and the river - a classic tale of aquatic adventure! So, here's the deal: the boat's speed in still water is 1.95m/s, but unfortunately, it has to deal with a pesky current that flows at 1.20m/s. So, how do we figure out the boat's speed with respect to the shore?

Imagine the boat is having a conversation with the river:

Boat: "Hey, river buddy, I want to go straight across. Can you help me out?"
River: "Sure thing, amigo! But hey, I've got this current that's trying to push you sideways. Just a friendly reminder!"

Now, to determine the boat's speed with respect to the shore, we have to combine the forces of the boat's speed in still water and the current's speed. It's like adding two vectors - but don't worry, I won't get all math-y on you!

So, it's like you're creating a triangle with the boat's speed in still water as one side and the current's speed as the other side. To find the resulting speed of the boat, you need to measure the length of that hypotenuse - that's your answer!

So, you're not far off, my friend! Just use the Pythagorean theorem, which tells you that the square of the hypotenuse is equal to the sum of the squares of the other two sides. In other words:

Boat's speed with respect to the shore = sqrt((1.95^2) + (1.20^2))

And that should give you the magnitude of the boat's speed with respect to the shore. Safe travels, sailor!

No, what you did is correct. In order to determine the speed of the boat with respect to the shore, you need to use the Pythagorean theorem.

To do this, you can use the formula:

speed of boat with respect to shore = sqrt((speed of boat in still water)^2 + (speed of the river current)^2)

Plugging in the values you provided:

speed of boat with respect to shore = sqrt((1.95m/s)^2 + (1.20m/s)^2)

Calculating this expression will give you the correct speed of the boat with respect to the shore.

No, there doesn't appear to be anything wrong with the way you approached the problem. To determine the speed of the boat with respect to the shore, you can use the Pythagorean theorem.

In this case, the boat's speed in still water is given as 1.95 m/s, and the speed of the river's current is given as 1.20 m/s. To find the boat's speed with respect to the shore, you can treat the boat's velocity vector and the river current's velocity vector as perpendicular sides of a right triangle. The boat's speed with respect to the shore can be thought of as the hypotenuse of this triangle.

You correctly used the Pythagorean theorem to calculate the boat's speed with respect to the shore:

√(1.95^2 + 1.20^2)

Squaring the magnitudes of the given speeds and adding them together is the correct approach. The square root of the sum gives you the magnitude of the resultant velocity vector.

Therefore, your calculations are correct, and you will get the speed of the boat with respect to the shore by evaluating this expression. In this case, √(1.95^2 + 1.20^2) equals approximately 2.29 m/s. So, the speed of the boat with respect to the shore is 2.29 m/s.