NH4OH + H2O =
NH4OH breaks down into NH3 and H2O
and ionizes to NH4^+ + OH^-. In fact,
NH3 + HOH ==> NH4^+ + OH^-
The chemical equation you provided represents the reaction between ammonium hydroxide (NH4OH) and water (H2O). This reaction is known as the ionization or dissociation of NH4OH in water.
To determine the products of this reaction, we need to understand the properties of ammonium hydroxide. NH4OH is an example of a weak base, which means it partially dissociates in water to produce hydroxide ions (OH-) and ammonium ions (NH4+).
The equation can be written as follows:
NH4OH + H2O --> NH4+ + OH-
In this equation, ammonium hydroxide (NH4OH) reacts with water (H2O) to produce ammonium ions (NH4+) and hydroxide ions (OH-). It's important to note that the ammonium cation (NH4+) remains unchanged during this reaction.
The resulting solution will be basic due to the presence of hydroxide ions (OH-).