How many newtons of force are necessary to accelerate a 0.0050 kg mass at the acceleration (a) of 9.81 m/s2 with the force expressed in the correct number of significant figures? (F = ma)
0.04905 N
0.049 N
0.05 N
4.91 × 102 N
Please help me :( It's just one little question.
9.81 has three sig figs.
.0050 is two figs, the 50 on the end
.0050 * 9.981 = .04905
which to two sig figs is .049 N
so
0.049
No problem! I can help you with that. To find the force (F) required to accelerate an object, you can use the formula F = ma, where m is the mass of the object and a is the acceleration.
In this case, the mass (m) is 0.0050 kg and the acceleration (a) is 9.81 m/s^2. By substituting these values into the formula, we can calculate the force:
F = (0.0050 kg) * (9.81 m/s^2) = 0.04905 N
Since the question asks for the answer in the correct number of significant figures, the correct answer is 0.049 N.
Sure, I'd be happy to help you with this question!
To find the force (F) required to accelerate an object, we can use the equation F = ma, where F is the force, m is the mass, and a is the acceleration.
Given:
- Mass (m) = 0.0050 kg
- Acceleration (a) = 9.81 m/s^2
Now, we can substitute these values into the equation F = ma:
F = (0.0050 kg)(9.81 m/s^2)
F ≈ 0.04905 N
Next, we need to express the answer using the correct number of significant figures. In this case, the least number of significant figures in the given values is 2 (0.0050 has 2 significant figures and 9.81 has 3 significant figures). Therefore, we need to round the answer to 2 significant figures.
Rounding 0.04905 N to 2 significant figures gives us:
0.049 N
So, the correct answer, with the force expressed in the correct number of significant figures, is: 0.049 N.
I hope this explanation helps! Let me know if you have any further questions.