The principal is choosing between 2 field tripS. The firt costs 600 dollars. The 2nd costs $240 plus $40 per students. For wat # of students is the 1trip less expensive?
you want to find where
600 < 240+40n
9 < n
How do u know wat way direction to put the inequality
To find out for what number of students the first trip is less expensive than the second trip, we need to compare the costs of both trips.
Let's assume the number of students is represented by 'x'.
For the first trip, the cost is a fixed $600.
For the second trip, the cost is $240 plus $40 per student. Therefore, the cost for the second trip can be calculated as (240 + 40x).
To find the number of students for which the first trip is less expensive, we need to set up an inequality:
First Trip Cost < Second Trip Cost
So, we have the inequality: 600 < (240 + 40x)
To solve this inequality, let's isolate 'x':
600 - 240 < 40x
360 < 40x
Now, divide both sides of the inequality by 40:
9 < x
Therefore, for any number of students greater than 9, the first trip will be less expensive than the second trip.