Question

the turning point for y= x^2-8x+2 is:

A (2,-16)
B (16,2)
C (8,-2)
D (-8,2)
E (4,-14)

Answer 1

you can rewrite it as

y = x^2-8x+16 + 2-16
y = (x-4)^2 - 14

Now it should be clear where the turning point (vertex) is.