FIND THE X INTERCEPTS OF THE GRAPH OF THE EQUATION pleaze explain thanks
1)Y=x to the second power+ 2x -8
2) Y=6X TO THE SECOND PoWER -x-12
The x intercepts are where the equation Y is equal to 0. So, just set up equation:
0 = x^2 + 2x - 8.
can you take it from here??
To find the x-intercepts of a graph, you need to determine the values of x for which y equals zero. In other words, to find the x-intercepts, set y equal to zero and solve for x.
Let's go through the process step by step for each equation:
1) Y = x^2 + 2x - 8
To find the x-intercepts, set y = 0:
0 = x^2 + 2x - 8
This equation is a quadratic equation, so we can solve it by factoring, completing the square, or using the quadratic formula. In this case, we'll use factoring.
Factor the quadratic expression:
0 = (x - 2)(x + 4)
Now, set each factor equal to zero and solve for x:
x - 2 = 0 => x = 2
x + 4 = 0 => x = -4
Therefore, the x-intercepts of the graph of the equation are x = 2 and x = -4.
2) Y = 6x^2 - x - 12
Set y = 0 to find the x-intercepts:
0 = 6x^2 - x - 12
Factor the quadratic expression:
0 = (2x + 3)(3x - 4)
Now, set each factor equal to zero and solve for x:
2x + 3 = 0 => 2x = -3 => x = -3/2
3x - 4 = 0 => 3x = 4 => x = 4/3
Therefore, the x-intercepts of the graph of the equation are x = -3/2 and x = 4/3.
By following these steps, you can find the x-intercepts of any given equation.