calculate the molarity of a solution made by dissolving 0.750 grams of Na2SO4 in enough water to form exactly 850 mL of solution.
that is right. but if it is 0.850 grams of Na2s04 it is completely diffrent.
I don't know what Aron is talking about.
mols Na2SO = grams/molar mass = ?
M = mols/L = ?mols/0.850L = zxx
Answerthe question
To calculate the molarity of a solution, we need to know the number of moles of solute (Na2SO4) and the volume of the solution.
Step 1: Calculate the number of moles of Na2SO4:
To do this, we need to know the molar mass of Na2SO4, which is 22.99 g/mol for Na, 32.07 g/mol for S, and 16.00 g/mol for O.
Substituting these values, we can calculate:
Na2SO4 molar mass = 2(22.99 g/mol) + 32.07 g/mol + 4(16.00 g/mol) = 142.04 g/mol
Next, we can calculate the number of moles of Na2SO4 using the given mass:
Number of moles = Mass / Molar mass
Number of moles = 0.750 g / 142.04 g/mol = 0.005277 mol
Step 2: Calculate the volume of the solution in liters:
The given volume is in milliliters, so we need to convert it to liters by dividing by 1000:
Volume = 850 mL / 1000 mL/L = 0.850 L
Step 3: Calculate the molarity:
Molarity (M) is defined as moles of solute divided by liters of solution.
Molarity = Moles / Volume
Molarity = 0.005277 mol / 0.850 L = 0.0062 M (rounded to four significant figures)
Therefore, the molarity of the solution made by dissolving 0.750 grams of Na2SO4 in enough water to form exactly 850 mL of solution is approximately 0.0062 M.