A golf ball of mass 30.0 grams is struck by a 4.00 kg golf club for a time of 3.00 ms. If the golf ball obtains a velocity of 25.0 m/s after being struck then with what force did the club strike the golf ball?
a. 2.50 N
b. 7.50 N
c. 250 N
d. 750 N
e. 25.0 N
To find the force with which the club struck the golf ball, we can use Newton's second law of motion:
Force = mass × acceleration
First, we need to find the acceleration of the golf ball. We can use the equation:
acceleration = (final velocity - initial velocity) / time
Given:
Mass of the golf ball (m) = 30.0 grams = 0.030 kg
Final velocity (v) = 25.0 m/s
Time (t) = 3.00 ms = 0.003 s
Using the equation for acceleration, we can calculate it as follows:
acceleration = (25.0 m/s - 0) / 0.003 s
acceleration = 8333.33 m/s^2
Now, using Newton's second law, we can find the force:
Force = mass × acceleration
Force = 0.030 kg × 8333.33 m/s^2
Force = 250 N
Therefore, the force with which the club struck the golf ball is 250 N, which corresponds to option c.
To find the force with which the club struck the golf ball, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the golf ball is 30.0 grams, which is equal to 0.030 kilograms. The velocity of the ball changes from 0 to 25.0 m/s in a time of 3.00 ms, which is equal to 0.003 seconds.
To find the acceleration, we can use the formula:
acceleration (a) = (final velocity - initial velocity) / time
= (25.0 m/s - 0 m/s) / 0.003 s
= 8333.33 m/s^2
Now, we can calculate the force using Newton's second law:
force (F) = mass (m) * acceleration (a)
= 0.030 kg * 8333.33 m/s^2
= 250 N
Therefore, the force with which the club struck the golf ball is 250 N. So, the correct option is c. 250 N.