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Use the Rational Zero Theorum and Descartes Rule of Signs as an aid in obtaining the first root.
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Solve the given polynomial equation. Use the Rational Zero Theorem and Descartes's Rule of Signs as an aid in obtaining the
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2x^3 - 5x^2 - 5x - 1 = 0 let f(x) = 2x^3 - 5x^2 - 5x - 1 try f(1) = 2 - 5 - 5 - 1 ≠ 0 try f(-1) =
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use the rational zero theorem and descartes’ rule of signs to assist you in finding all real and imaginary roots for
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RRT says roots are ±1,±2,±4 DRT says there are at most 2 positive and 2 negative roots so, a
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List the possible rational roots of each equation. Then determine the rational roots.
6x^4+35x^3-x^2-7x-1 The answer in the back
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To determine the possible rational roots of a polynomial equation, you can use the Rational Root
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Find all the zeros of the polynomial function by using the Rational Zero Theorem, Descartes Rule of Signs and Synthetic
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DRS says there are 2 or 0 positive roots 1 negative root RZT says look for roots among ±1,5,7,35
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3. Given the function f(x)=2x^4-4x^2+4x-8
a. Use the rational root theorem to list all possible rational roots b. Use Descartes
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#3 what about the theorems do you not understand? (b) changes of sign of f(x) = 3, so there are 1 or
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Use the rational zero theorem, Descartes rule of signs, and the theorem on bounds as aids in finding all real and imaginary
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Using Descartes' Rule of Signs, solve:
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Descartes' Rule of Signs does not actually solve the equation it merely tells you how many real
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Use descartes rule of signs
H(x)=2x^3+5x^2-31x-15
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AAAaannndd the bot gets it wrong yet again! you clearly do not know how to count sign changes. H(x)
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Please help me.
Use Descartes' rule of signs to describe the roots for each polynomial function. 3. m(x)=x^3+3x^2-18x-40
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1 positive, 2 or 0 negative check: http://www.wolframalpha.com/input/?i=x^3%2B3x^2-18x-40
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x^4+16x^2+7x-11=0 Descartes’ rule of signs to find the nature of the roots of the equation
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I would suggest you print out and study this example http://www.purplemath.com/modules/drofsign.htm
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