how do i make 100ml of (0.01mol/L) KMnO4 out of 10.0ml(0.10mol/L)KMnO4
You are diluting it by a factor of ten. One part original concentrated solution, nine parts solvent. In this, the original solution is already measured for you.
i don't understand what you mean
Just follow Bob Pursley's advice. Add 1 part concentrated solution to 9 parts water. If you took your 10 mL and added 89 mL water, what would be the final concentration and how much would you have? Another way to look at it is
M x mL = M x mL
0.01 x 100 mL = 0.1 x ?
solve for ?ml = xx
thanks
To make 100ml of a 0.01 mol/L KMnO4 solution from a 10.0 ml 0.10 mol/L KMnO4 solution, you will need to dilute the given solution.
Here is a step-by-step guide on how to do it:
1. Calculate the amount of KMnO4 required:
- Given that the initial concentration (C1) is 0.10 mol/L and the final concentration (C2) is 0.01 mol/L, you can use the formula C1V1 = C2V2 to find the volume (V1) of the initial solution required:
- V1 = (C2 * V2) / C1
- V1 = (0.01 mol/L * 100 ml) / 0.10 mol/L
- V1 = 10 ml
2. Measure 10.0 ml of the 0.10 mol/L KMnO4 solution using a graduated cylinder or a pipette.
3. Add the measured 10.0 ml of the 0.10 mol/L KMnO4 solution to a clean and empty container.
4. Add distilled water to the container until the total volume reaches 100 ml. You can use a graduated cylinder to accurately measure the volume.
5. Gently mix the solution to ensure the components are evenly distributed.
Now, you have successfully prepared 100 ml of a 0.01 mol/L KMnO4 solution by diluting the given 10.0 ml 0.10 mol/L KMnO4 solution.