A motor cycle starts from rest and reaches a speed of 6m/s after travelling with uniform acceleration for 3s. What is his acceleration?
a = change in velocity / change in time
= (6-0)/(3-0) = 2 m/s^2
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To find the acceleration of the motorcycle, we can use the equation of motion:
\[v = u + at\]
where:
v = final velocity (6 m/s),
u = initial velocity (0 m/s, since the motorcycle starts from rest),
a = acceleration (unknown),
t = time (3 s).
Substituting the given values into the equation, we have:
\[6 = 0 + a \cdot 3\]
Simplifying the equation, we get:
\[6 = 3a\]
To find the acceleration (\(a\)), we can divide both sides of the equation by 3:
\[a = 6/3\]
Thus, the acceleration of the motorcycle is \(2 \, \text{m/s}^2\).
In summary, the acceleration of the motorcycle is 2 m/s^2.