How would you prepare 10 mL of 0.08 M NaCl in sodium acetate buffer? (Stock Sodium acetate buffer: 0.1 M)

To prepare 10 mL of a 0.08 M NaCl solution in sodium acetate buffer, you will need to calculate the amount of NaCl and buffer solution required. Here are the steps:

1. Determine the moles of NaCl needed:
Molarity (M) = Moles (mol) / Volume (L)

Rearranging the formula, Moles (mol) = Molarity (M) × Volume (L)

Moles (mol) = 0.08 M × 0.01 L (10 mL converted to liters)
Moles (mol) = 0.0008 mol

2. Calculate the volume of the buffer solution needed:
Desired final volume = 10 mL (from the question)

The total volume will be the sum of the NaCl solution and the buffer solution. Since the buffer used is at a higher concentration, you will dilute it to achieve the desired final concentration. The number of moles of sodium acetate buffer should be equal to the number of moles in the NaCl solution.

Moles (mol) = 0.0008 mol (from step 1)

Molarity of the buffer solution = 0.1 M (from the question)

Volume of buffer solution = Moles (mol) / Molarity (M)
Volume of buffer solution = 0.0008 mol / 0.1 M
Volume of buffer solution = 0.008 L (or 8 mL)

3. Prepare the solution:
Take 8 mL of the 0.1 M sodium acetate buffer and transfer it to a container.
Add 2 mL of distilled water to the buffer solution to reach the final volume of 10 mL.
Mix the solution thoroughly to ensure homogeneity.

Now you have 10 mL of a 0.08 M NaCl solution in sodium acetate buffer.