It says; the temperature of 50g of water was raised from 5 degrees celsius to 85 degrees celsius. then it asks me: what amount or mass of water was heated? how do i find that out?
To find out the mass of water that was heated, you can use the formula:
Q = mcΔT
Where:
Q represents the heat energy absorbed or released by the substance (in this case, water)
m represents the mass of the substance being heated or cooled
c represents the specific heat capacity of the substance (for water, it is approximately 4.18 J/g°C)
ΔT represents the change in temperature (final temperature minus initial temperature)
In this case, you have the following values:
Initial temperature (Ti) = 5°C
Final temperature (Tf) = 85°C
Change in temperature (ΔT) = Tf - Ti = 85°C - 5°C = 80°C
Specific heat capacity of water (c) = 4.18 J/g°C
Now, you can rearrange the formula to solve for the mass (m):
m = Q / (c * ΔT)
Since you are given the temperature change (ΔT) and the specific heat capacity (c) of water, you need to find the heat energy (Q).
The heat energy can be calculated using the equation:
Q = mcΔT
Substituting the known values:
Q = (50g) * (4.18 J/g°C) * 80°C
After calculating Q, you can substitute the value of Q into the equation for mass (m):
m = Q / (c * ΔT)
Finally, calculate the mass (m) to find the amount or mass of water that was heated.