calculate how to make 10 mL of 15:85 ethyl acetate:hexane solution
from 2 mL of 5:95 ethyl acetate:hexane, using pure hexane and pure ethyl
acetate.
To calculate how to make 10 mL of a 15:85 ethyl acetate:hexane solution, we need to determine the volumes of pure ethyl acetate and pure hexane required to achieve the desired ratio.
First, let's break down the given information:
- We have 2 mL of a 5:95 ethyl acetate:hexane solution.
- We need to make a 10 mL solution with a ratio of 15:85 ethyl acetate:hexane.
Step 1: Calculate the volume of ethyl acetate in the starting solution:
The starting solution is 5:95 ethyl acetate:hexane, with a total volume of 2 mL. To determine the volume of ethyl acetate in this solution, we multiply the total volume (2 mL) by the ethyl acetate ratio (5/100):
Volume of ethyl acetate = 2 mL * (5/100) = 0.1 mL
Step 2: Calculate the volume of hexane in the starting solution:
Similarly, to determine the volume of hexane in the starting solution, we multiply the total volume (2 mL) by the hexane ratio (95/100):
Volume of hexane = 2 mL * (95/100) = 1.9 mL
Step 3: Calculate the volumes of pure ethyl acetate and hexane required to achieve the desired ratio:
In the desired 15:85 ethyl acetate:hexane solution, we need a total volume of 10 mL. We'll assume x mL of pure ethyl acetate is required, and the remaining volume (10 - x) mL will be pure hexane.
Using the given ratio, we can write the following equation:
0.1 mL + x mL (ethyl acetate) = 15/100 * 10 mL (total volume)
x + 0.1 = 1.5
x = 1.5 - 0.1 = 1.4 mL
Therefore, we need 1.4 mL of pure ethyl acetate and the remaining Volume of hexane = 10 mL - 1.4 mL = 8.6 mL of pure hexane to make a 10 mL solution of 15:85 ethyl acetate:hexane.