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Let y=cos x+sin x/cos x -sin x. Find dy/dx
1 answer
dy/dx= cos + sin / cos - sin
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expres the following as sums and differences of sines or cosines
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Reduce the following to the sine or cosine of one angle:
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Given:
cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < 2pi Find: sin (v + u) cos (v - u) tan (v + u) First compute or list
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if cos u=3/5 cos v=5/13 then sin u=4/5 and sin v=12/13 then sin(v+u)=sinv cos u+cos v sin u
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it says to verify the following identity, working only on one side:
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I do not understand how to do this problem
((sin^3 A + cos^3 A)/(sin A + cos A) ) = 1 - sin A cos A note that all the trig terms
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use graphic techiques in radians I found that it is roughly equal to -.5 sin [ 20.42036^-1(x +
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Show that sin(x+pi)=-sinx.
So far, I used the sum formula for sin which is sin(a+b)=sin a cos b+cos a sin b. sin(x+pi)=sin x cos
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in(x+pi)=sin x cos pi+cos x sin pi but cosPI=-1, sin PI=0 sin(x+PI)= -sinx
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Find the velocity, v(t), for an object moving along the x-axis if the acceleration, a(t), is a(t) = cos(t) - sin(t) and v(0) =
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v(t) = sint + cost + c 0+1+c = 3
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Find the velocity, v(t), for an object moving along the x-axis if the acceleration, a(t), is a(t) = cos(t) - sin(t) and v(0) = 3
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v(t) = ∫ a(t) dt = ∫ cost-sint dt = sint+cost+C Now plug in (0,3) to find C
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Find the velocity, v(t), for an object moving along the x-axis if the acceleration, a(t), is a(t) = cos(t) − sin(t) and v(0) =
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Find the velocity, v(t), for an object moving along the x-axis in the acceleration, a(t), is a(t)=cos(t)-sin(t) and v(0)=3
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a = cost - sint = dv/dt so, v = sint + cost + C now solve v(0) = 3 to find C
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