slope and y intercept form of these two problems?
Y-5=1/3(x-9)
2y+6a-4x=0
For the second one I have this but I'm not sure what to do next
Add 4x to both sides, so you would have 2y+6a=4x
Then I divided 2y by 2 and 4x by 2 and got y+6a=4x
Next I subtracted 6a from both sides and got y=2x-6a
Am I right so far? If so what do I do next?
2nd:
2y + 6a - 4x = 0
you want to "isolate" the y, so everybody else to the other side
2y = 4x - 6a
divide each term by 2 , (you only divided one term and not the others)
y = 2x - 3a
the 1st:
y - 5 = (1/3)(x-9)
y = (1/3)x - 3 + 5
y = (1/3)x + 2
To find the slope-intercept form of the given equations, we need to rearrange each equation and isolate y.
1. Y - 5 = (1/3)(x - 9)
To convert this equation to slope-intercept form (y = mx + b), we'll start by distributing the factor of (1/3) to the terms inside the parentheses:
Y - 5 = (1/3)x - (1/3)(9)
Y - 5 = (1/3)x - 3
Next, we'll simplify the equation by adding 5 to both sides to isolate Y:
Y = (1/3)x - 3 + 5
Y = (1/3)x + 2
Therefore, the slope-intercept form of the first equation is y = (1/3)x + 2.
2. 2y + 6a - 4x = 0
To convert this equation to slope-intercept form (y = mx + b), we'll first isolate the y-term:
2y = 4x - 6a
y = (4x - 6a) / 2
y = 2x - 3a
Therefore, the slope-intercept form of the second equation is y = 2x - 3a.
To find the slope-intercept form of the given equations, we need to rearrange the equations to solve for y.
1. Y-5=1/3(x-9)
First, distribute 1/3 to (x-9):
Y - 5 = 1/3x - 3
Next, isolate Y by adding 5 to both sides of the equation:
Y = 1/3x - 3 + 5
Simplifying,
Y = 1/3x + 2
Therefore, the slope-intercept form of the first equation is y = 1/3x + 2.
2. 2y + 6a - 4x = 0
First, isolate y by subtracting 6a and 4x from both sides:
2y = 4x - 6a
Next, divide the entire equation by 2 to solve for y:
y = 2x - 3a
Therefore, the slope-intercept form of the second equation is y = 2x - 3a.
In both cases, the slope-intercept form of the equation is y = mx + b, where m represents the slope and b represents the y-intercept.