what is the mass in grams of the following 6.78 mol of NaI
Na=23g
l=7g
therefore:-
1mol=23+7g=30g
6.78=(x)g
x=30*6.78
x=203.4g
To determine the mass in grams of 6.78 mol of NaI (sodium iodide), you need to know the molar mass of NaI. The molar mass of an element or compound is the mass in grams of one mole of that substance.
The atomic mass of Na (sodium) is approximately 22.99 g/mol, and the atomic mass of I (iodine) is approximately 126.90 g/mol. Therefore, you can calculate the molar mass of NaI (sodium iodide) by adding the atomic masses of Na and I:
Na: 22.99 g/mol
I: 126.90 g/mol
Molar mass of NaI = 22.99 g/mol + 126.90 g/mol = 149.89 g/mol
Now, you can calculate the mass in grams of 6.78 mol of NaI using the molar mass:
Mass of 6.78 mol of NaI = 6.78 mol x 149.89 g/mol = 1016.32 grams
Therefore, the mass of 6.78 mol of NaI is 1016.32 grams.
To find the mass in grams of a given number of moles, you need to know the molar mass of the substance.
The molar mass of NaI (sodium iodide) can be calculated by adding the atomic masses of its constituent elements: sodium (Na) and iodine (I).
According to the periodic table, the atomic mass of sodium (Na) is approximately 22.99 grams/mol, and the atomic mass of iodine (I) is approximately 126.90 grams/mol.
The molar mass of NaI can be calculated as follows:
Molar Mass of NaI = (Molar Mass of Na) + (Molar Mass of I)
= (22.99 g/mol) + (126.90 g/mol)
Molar Mass of NaI = 149.89 g/mol
Now, to find the mass of 6.78 moles of NaI, you can use the following equation:
Mass (in grams) = (Number of moles) × (Molar mass)
Mass (in grams) = 6.78 mol × 149.89 g/mol
Finally, solve for the mass:
Mass (in grams) ≈ 1016.43 grams
Therefore, the mass in grams of 6.78 moles of NaI is approximately 1016.43 grams.