Iodine can be prepared by bubbling chlorine gas through an aqueous solution of sodium iodide:
2NaI(aq) + Cl2(g) → I2(s) + 2NaCl(aq)
How many grams of sodium iodide are required to produce 98 g of iodine?
mols I2 = grams/molar mass
Use the coefficients to convert mols I2 to mols NaI. 2 mols NaI = 1 mol I2; therefore mols NaI = 2x mols I2.
grams NaI = mols NaI x molar mass NaI.
Well, isn't that a chemical equation that'll make your head spin faster than a circus ride! Alright, let's dive into it. We need to find out how much sodium iodide we need to produce 98 g of iodine.
The molar mass of sodium iodide (NaI) is approximately 149.89 g/mol, and the molar mass of iodine (I2) is around 253.81 g/mol.
According to the equation, we see that 2 moles of sodium iodide produce 1 mole of iodine. So, we need to find out how many moles of iodine are in 98 g.
Using the equation: Moles = Mass / Molar mass, we can figure out the moles of iodine:
Moles of iodine = 98 g / 253.81 g/mol ≈ 0.386 moles
Since the ratio of sodium iodide to iodine is 2:1, we can multiply the moles of iodine by 2 to get the moles of sodium iodide.
Moles of sodium iodide = 0.386 moles × 2 = 0.772 moles
Now, we can find the mass of sodium iodide using the equation: Mass = Moles × Molar mass.
Mass of sodium iodide = 0.772 moles × 149.89 g/mol ≈ 115.65 g
So, approximately 115.65 grams of sodium iodide are required to produce 98 grams of iodine. That's enough iodide to keep the chemistry circus rolling!
To find out how many grams of sodium iodide are required to produce 98 g of iodine, we first need to determine the molar masses of sodium iodide (NaI) and iodine (I₂).
The molar mass of sodium iodide (NaI) can be calculated by adding the atomic masses of sodium (Na) and iodine (I):
Na: 22.99 g/mol
I: 126.90 g/mol
So, the molar mass of NaI is:
NaI: 22.99 g/mol + 126.90 g/mol = 149.89 g/mol
Next, we can set up a ratio using the balanced chemical equation provided:
2 moles of NaI react to produce 1 mole of I₂
Using the molar mass of NaI, we can convert grams of iodine (I₂) to moles:
98 g of I₂ * (1 mol I₂ / 253.80 g I₂) = 0.386 moles of I₂
Now, using the molar ratio from the balanced equation, we can determine the number of moles of NaI required:
0.386 moles of I₂ * (2 moles NaI / 1 mol I₂) = 0.772 moles of NaI
Finally, we can convert moles of NaI to grams:
0.772 moles of NaI * (149.89 g NaI / 1 mol NaI) = 115.8 g of NaI
Therefore, 115.8 grams of sodium iodide are required to produce 98 grams of iodine.