The molar enthalpy of combustion of glucose is -2803 kJ. A mass of 1.000 g glucose is combusted in a bomb calorimeter. If the calorimeter contains 875 g H2O and the bomb has a heat capacity of 457 J/C, what is the temperature increase of the bomb calorimeter? the specific heat capacity of water is 4.184 J/g*K and the molar mass of glucose is 180.2 g/mol.

See your other post where I responded.

To solve this problem, we need to first calculate the heat released by the combustion of glucose using the molar enthalpy of combustion. Then, we can use this heat value to determine the temperature increase of the bomb calorimeter using its heat capacity and the heat absorbed by the water.

Step 1: Calculate the moles of glucose:
Molar mass of glucose (C6H12O6) = 180.2 g/mol
Mass of glucose = 1.000 g

moles of glucose = mass / molar mass
moles of glucose = 1.000 g / 180.2 g/mol

Step 2: Calculate the heat released by the combustion of glucose:
Molar enthalpy of combustion of glucose = -2803 kJ/mol
moles of glucose = 1.000 g / 180.2 g/mol

heat released by the combustion of glucose = molar enthalpy of combustion * moles of glucose
heat released by the combustion of glucose = -2803 kJ/mol * (1.000 g / 180.2 g/mol)

Step 3: Convert heat released to J for consistency:
heat released by the combustion of glucose = -2803 kJ/mol * (1.000 g / 180.2 g/mol) * 1000 J/kJ

Step 4: Calculate the heat absorbed by the water:
Specific heat capacity of water = 4.184 J/g*K
Mass of water = 875 g

heat absorbed by the water = specific heat capacity * mass of water * temperature increase
temperature increase = heat absorbed by the water / (specific heat capacity * mass of water)

Step 5: Calculate the temperature increase of the bomb calorimeter:
Heat capacity of the bomb calorimeter = 457 J/C

temperature increase of the bomb calorimeter = heat absorbed by the water / heat capacity of the bomb calorimeter

Now, let's substitute the values and calculate the temperature increase:

temperature increase = (heat released by the combustion of glucose) / (specific heat capacity of water * mass of water) / heat capacity of the bomb calorimeter

Substituting the values:
temperature increase = [-2803 kJ/mol * (1.000 g / 180.2 g/mol) * 1000 J/kJ] / (4.184 J/g*K * 875 g) / 457 J/C

Simplifying the equation will give the final result for the temperature increase of the bomb calorimeter.