This is a three part problem I need help in figuring out pleaseI
n each of the questions below you are going to determine a different type of balanced equation for the same reaction. Make sure your equations have the lowest whole number coefficients possible. Indicate the physical states of the reactants and products. Refer to Solubility rules as necessary.
Barium sulfate is used when X-rays of the gastrointestinal tract are made. Barium sulfate can be prepared by reacting barium chloride with dilute sulfuric acid. From this description, determine the balanced formula unit equation. Enter your answer as the sum of the coefficients of all of the species. Make sure your equation has the lowest whole number coefficeints possible. Refer to solubility rules as necessary.
In water purification small solid particles are often ``trapped'' as aluminum hydroxide precipitates and fall to the bottom of the sedimentation pool. Aluminum sulfate reacts with calcium hydroxide (from lime) to form aluminum hydroxide and calcium sulfate. Determine the total ionic equation for the reaction stated. Again, enter your answer as the sum of the coefficients.
Bones are mostly calcium phosphate. Calcium chloride reacts with potassium phosphate to form calcium phosphate and potassium chloride. From this information, write the balanced net ionic equation. Answer as the sum of the coefficients yet again.
H2SO4(aq) + BaCl2(aq) --> BaSO4(s) + 2HCl(aq)
Note: I wouldn't want to prepare it this way if I were to drink it. I don't want to drink the HCl.
2Al^3+(aq) + 3SO4^2-(aq) + 3Ca^2+(aq) + 6OH^-(aq) ==> 2Al(OH)3(s) + 3CaSO4(s)
3Ca^2+(aq) + 2PO4^3-(aq) ==> Ca3(PO4)2(s)
To determine the balanced formula unit equation for the first reaction:
Step 1: Identify the reactants and products.
Reactants: Barium chloride (BaCl2) and dilute sulfuric acid (H2SO4)
Product: Barium sulfate (BaSO4)
Step 2: Write the unbalanced equation.
BaCl2 + H2SO4 → BaSO4 + HCl
Step 3: Balance the equation.
The equation is already balanced in terms of the number of atoms present. However, we need to consider solubility rules to determine the physical states (s, l, g, or aq) of the species. According to solubility rules, barium sulfate is insoluble and exists as a solid (s), while hydrochloric acid (HCl) is soluble and exists as an aqueous solution (aq). Thus, the balanced formula unit equation is:
BaCl2(aq) + H2SO4(aq) → BaSO4(s) + 2HCl(aq)
To determine the total ionic equation for the second reaction:
Step 1: Identify the reactants and products.
Reactants: Aluminum sulfate (Al2(SO4)3) and calcium hydroxide (Ca(OH)2)
Products: Aluminum hydroxide (Al(OH)3) and calcium sulfate (CaSO4)
Step 2: Write the unbalanced equation.
Al2(SO4)3 + 3Ca(OH)2 → 2Al(OH)3 + 3CaSO4
Step 3: Break down the soluble compounds into their constituent ions.
Al2(SO4)3 → 2Al3+ + 3SO4^2-
3Ca(OH)2 → 6Ca2+ + 6OH-
2Al(OH)3 → 2Al3+ + 6OH-
3CaSO4 → 3Ca2+ + 3SO4^2-
Step 4: Write the total ionic equation.
2Al3+ + 3SO4^2- + 6Ca2+ + 6OH- → 2Al(OH)3 + 3CaSO4
To determine the balanced net ionic equation for the third reaction:
Step 1: Identify the reactants and products.
Reactants: Calcium chloride (CaCl2) and potassium phosphate (K3PO4)
Products: Calcium phosphate (Ca3(PO4)2) and potassium chloride (KCl)
Step 2: Write the unbalanced equation.
3CaCl2 + 2K3PO4 → Ca3(PO4)2 + 6KCl
Step 3: Break down the soluble compounds into their constituent ions.
3CaCl2 → 6Ca2+ + 6Cl-
2K3PO4 → 6K+ + 2PO4^3-
Ca3(PO4)2 → 3Ca2+ + 2PO4^3-
Step 4: Write the net ionic equation.
6Ca2+ + 6Cl- + 6K+ + 2PO4^3- → Ca3(PO4)2 + 6KCl
Note: The coefficients in front of the ions may vary, but the sum of the coefficients should be the same on both sides of the equation.