Together, Misty and Keith caught 29 fish. Keith caught 5 fewer fish than Misty. How many did they each catch?
Let M = Misty
M + M-5 = 29
2M = 29 + 5
2M = 34
M = 17
I have no idea.
Can it be done?I don't know I'm in third grade.
This problem was on a paper in school and
even she didn't know how to do it.
To solve this problem, we'll start by setting up equations based on the information provided.
Let's assume that Misty caught X fish.
Since Keith caught 5 fewer fish than Misty, Keith's number of fish can be represented as (X - 5).
According to the problem, the total number of fish caught by both Misty and Keith is 29.
So our equation becomes:
X + (X - 5) = 29
Now, let's solve for X.
Combining like terms, we get:
2X - 5 = 29
Adding 5 to both sides of the equation, we get:
2X = 34
Dividing both sides of the equation by 2, we get:
X = 17
So Misty caught 17 fish.
To find out how many fish Keith caught, we can substitute the value of X back into our equation (X - 5):
17 - 5 = 12
Therefore, Keith caught 12 fish.
In conclusion, Misty caught 17 fish while Keith caught 12 fish.