I figured all the parts of the problem except for the last one. Can you tell me what to do?
In the preparation of a mustard solution, an individual package of mustard was emptied into a beaker and the mass was determined to be 3.809 grams. The mustard was then dissolved in 50.0 ml. of distilled water. The total mass of the solution was found to be 49.401 grams. Calculate the weight percent of the mustard in the prepared solution.
7.7
The result of a micro-scale titration showed that 3.91E-5 moles of NaOH were required to titrate a 0.775 gram sample of mustard solution to an orange-red end point.
Calculate the number of grams of acetic acid in the sample of mustard solution.
2.35×10-3
Calculate the weight percent of acetic acid in this titrated sample.
0.30
Using the information provided in the questions above, calculate the weight percent of acetic acid in the original package of mustard prepared above???
To calculate the weight percent of acetic acid in the original package of mustard, we need to use the information provided in the previous questions.
First, let's start by finding the number of moles of acetic acid in the titrated sample. We were given that 3.91E-5 moles of NaOH were required to titrate a 0.775 gram sample of mustard solution to an orange-red end point. This means that the molar ratio between NaOH and acetic acid is 1:1. Therefore, we have 3.91E-5 moles of acetic acid in the sample.
Next, we can calculate the molar mass of acetic acid, which is C2H4O2. Carbon (C) has a molar mass of 12.01 g/mol, hydrogen (H) has a molar mass of 1.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol. Adding these up, we get:
2(12.01) + 4(1.01) + 2(16.00) = 60.05 g/mol
Now, we can calculate the mass of acetic acid in the sample by multiplying the number of moles by the molar mass:
Mass of acetic acid = 3.91E-5 moles * 60.05 g/mol = 2.35E-3 grams
Therefore, the number of grams of acetic acid in the sample of mustard solution is 2.35E-3 grams.
Finally, we can calculate the weight percent of acetic acid in the original package of mustard. We know that the mass of the mustard solution was found to be 49.401 grams. Since the mass of acetic acid is 2.35E-3 grams, we can use the formula:
Weight percent = (mass of acetic acid / mass of mustard solution) * 100
Weight percent = (2.35E-3 grams / 49.401 grams) * 100 = 0.0048%
Therefore, the weight percent of acetic acid in the original package of mustard prepared above is approximately 0.0048%.