I originally asked you the first question and I got the answer 7.7 but theres other parts to the problem but Im not sure what to do
In the preparation of a mustard solution, an individual package of mustard was emptied into a beaker and the mass was determined to be 3.809
grams. The mustard was then dissolved in 50.0 ml. of distilled water. The total mass of the solution was found to be 49.401 grams. Calculate the weight percent of the mustard in the prepared solution.
7.7
The result of a micro-scale titration showed that 3.91E-5 moles of NaOH were required to titrate a 0.775 gram sample of mustard solution to an orange-red end point.
Calculate the number of grams of acetic acid in the sample of mustard solution.
Calculate the weight percent of acetic acid in this titrated sample.
Using the information provided in the questions above, calculate the weight percent of acetic acid in the original package of mustard prepared above.
To find the weight percent of mustard in the prepared solution, you need to calculate the difference in mass before and after dissolving the mustard.
First, let's find the mass of the mustard. The mass of the mustard is given as 3.809 grams.
Next, subtract the mass of the mustard from the total mass of the solution to find the mass of the water. The total mass of the solution is given as 49.401 grams. So, the mass of water is 49.401 g - 3.809 g = 45.592 grams.
To calculate the weight percent of mustard in the solution, divide the mass of mustard by the total mass of the solution and multiply by 100:
Weight percent = (Mass of mustard / Total mass of solution) * 100
Weight percent = (3.809 g / 49.401 g) * 100
Weight percent ≈ 7.7%
Now, let's move on to the other parts of the problem.
To calculate the number of grams of acetic acid in the sample of mustard solution, you need to know the molar ratio between acetic acid and NaOH. Since it is not provided, we cannot calculate it.