Alump of lead with mass 0.50kg is dropped from a hight of 20m onto a hard surface. it doesn't rebound but remains there at rest for a long periods of time. what are Q,W,UFOR THE LEAD DURING THE PROCESS.

100 joule

72 72, 100J

you are right

72, 100J

To determine the energy changes for the lead during this process, we need to analyze the different types of energy involved.

1. Gravitational Potential Energy (Q):
The initial energy is in the form of gravitational potential energy, which depends on the mass (m) and height (h) of the object. The formula for gravitational potential energy is:
Q = m * g * h

In this case, the mass of the lead (m) is given as 0.50 kg, and the height (h) is 20 m. We also need the acceleration due to gravity (g), which is approximately 9.81 m/s². Plugging in these values, we get:
Q = 0.50 kg * 9.81 m/s² * 20 m

Calculating this gives us the initial gravitational potential energy (Q) of the lead.

2. Work Done (W):
In this scenario, the lead doesn't rebound but remains at rest on the hard surface. When an object comes to a stop, work is done to dissipate its kinetic energy. The work done can be calculated using the formula:
W = ΔK

Since the lead comes to rest, its final kinetic energy (K) is zero. Therefore, the work done (W) is equal to the initial kinetic energy (K) of the lead.

3. UFOR (Change in Internal Energy):
In this process, the lead remains at rest on the hard surface for a long period of time. This implies that there is no change in internal energy. Therefore, the change in internal energy (UFOR) of the lead is zero.

To summarize:
Q (Gravitational Potential Energy) = m * g * h
W (Work Done) = ΔK (initial kinetic energy)
UFOR (Change in Internal Energy) = 0 (no change)

Plug in the given values to calculate Q. However, it's important to note that W (work done) depends on the initial kinetic energy, which is not provided. Therefore, without that information, we cannot calculate the work done.