A 110 kg object moves in a horizontal straight line with an initial speed of 54 m/s. If it is stopped along that line with a deceleration of 1.90 m/s2 what magnitude of force is required?
F=ma
To find the magnitude of force required to stop the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, the object is decelerating, which means its acceleration is negative. Given that the deceleration is -1.90 m/s^2, we can use the following formula:
Force = Mass × Acceleration
The mass of the object is 110 kg, and the acceleration is -1.90 m/s^2.
Substituting these values into the formula, we get:
Force = 110 kg × (-1.90 m/s^2)
Calculating further, we find:
Force = -209 N
Therefore, the magnitude of force required to stop the object is 209 N. The negative sign indicates that the force is acting in the opposite direction of the object's motion.