write an.algebraic equation for autumn has,1 brother. this is 3 less than the number of brothers chase has,b

Let's call the number of brothers Chase has "C". According to the information given, Autumn has 1 brother, which can be represented as "A = 1". Now, we know that Autumn having 1 brother is 3 less than the number of brothers Chase has. In mathematical terms, we can say "A = C - 3".

Let's define the variable "b" as the number of brothers Chase has.

According to the given information, Autumn has one brother, which can be represented as:

Autumn's number of brothers = 1

Chase's number of brothers is 3 more than Autumn's number of brothers, so we can express it as:

Chase's number of brothers = Autumn's number of brothers + 3

Now, substituting the value of Autumn's number of brothers into the equation, we get:

Chase's number of brothers = 1 + 3

Simplifying this expression, we have:

Chase's number of brothers = 4

Therefore, the algebraic equation is:

Chase's number of brothers = 4, represented as b = 4.

To write an algebraic equation for this scenario, let's assign variables to represent the number of brothers each person has.

Let's say "A" represents the number of brothers Autumn has, and "C" represents the number of brothers Chase has.

According to the given information, Autumn has 1 brother. So we can write A = 1.

It is also mentioned that the number of brothers Autumn has is 3 less than the number of brothers Chase has. Mathematically, this can be expressed as A = C - 3.

Therefore, the algebraic equation for this scenario is A = C - 3, where "A" represents the number of brothers Autumn has and "C" represents the number of brothers Chase has.