Determine the mass of CuSO4.5H20 needed to make 250 mL of a .100M CuSO4.5H20 aqueous solution..
How many mols do you need? That M x L = ?
Then mol = grams/molar mass or
grams CuSO4.5H2O = mols CuSO4.5H2O x molar mass CuSO4.5H2O
To determine the mass of CuSO4·5H2O needed to make 250 mL of a 0.100 M CuSO4·5H2O solution, you need to follow these steps:
Step 1: Calculate the number of moles of CuSO4·5H2O required.
Molarity (M) is defined as moles of solute per liter of solution. In this case, the molarity is 0.100 M. We have a total volume of 250 mL, which is equivalent to 0.25 L (since 1 mL = 0.001 L).
Moles of CuSO4·5H2O = Molarity × Volume
Moles of CuSO4·5H2O = 0.100 mol/L × 0.25 L
Moles of CuSO4·5H2O = 0.025 mol
Step 2: Calculate the molar mass of CuSO4·5H2O.
CuSO4·5H2O consists of 1 Cu atom, 1 S atom, 4 O atoms, and 10 H atoms. To calculate the molar mass, we sum up the atomic masses of each element.
Cu: 63.55 g/mol
S: 32.07 g/mol
O: 16.00 g/mol (4 atoms since it is O4)
H: 1.01 g/mol (10 atoms since it is H10)
Molar mass of CuSO4·5H2O = (63.55 + 32.07 + 4 * 16.00 + 10 * 1.01) g/mol
Molar mass of CuSO4·5H2O = 249.69 g/mol
Step 3: Calculate the mass of CuSO4·5H2O needed.
Mass of CuSO4·5H2O = Moles of CuSO4·5H2O × Molar mass of CuSO4·5H2O
Mass of CuSO4·5H2O = 0.025 mol × 249.69 g/mol
Mass of CuSO4·5H2O = 6.24 g (rounded to two decimal places)
Therefore, you would need approximately 6.24 grams of CuSO4·5H2O to make 250 mL of a 0.100 M CuSO4·5H2O aqueous solution.
To determine the mass of CuSO4.5H2O needed, we need to use the molar concentration and volume of the solution. Here's the step-by-step process:
1. Start by finding the number of moles of CuSO4.5H2O that you need. You can do this using the formula: moles = concentration (M) × volume (L).
In this case, the concentration is 0.100 M (Molarity) and the volume is 250 mL (convert it to liters by dividing by 1000: 250 mL ÷ 1000 = 0.25 L).
moles = 0.100 M × 0.25 L = 0.025 moles
2. Next, we need to calculate the molar mass of CuSO4.5H2O. Add up the atomic masses of the elements in the compound, considering the subscripts:
Copper (Cu) = 63.55 g/mol
Sulfur (S) = 32.07 g/mol
Oxygen (O, in SO4) = 16.00 g/mol x 4 = 64.00 g/mol
Hydrogen (H, in H2O) = 1.01 g/mol x 10 = 10.10 g/mol
Oxygen (O, in H2O) = 16.00 g/mol x 5 = 80.00 g/mol
Adding up these atomic masses gives us the molar mass:
Molar mass = (63.55 g/mol) + (32.07 g/mol) + (64.00 g/mol) + (10.10 g/mol) + (80.00 g/mol)
= 249.72 g/mol
3. Finally, we can find the mass of CuSO4.5H2O needed using the calculated moles and molar mass:
mass = moles × molar mass
= 0.025 moles × 249.72 g/mol
≈ 6.24 grams
Therefore, to make 250 mL of a 0.100 M CuSO4.5H2O solution, you would need approximately 6.24 grams of CuSO4.5H2O.