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The life of tires manufactured by Omega Tires Inc is believed to be normally distributed with a mean of 110,000 km and a standard deviation of 5,000 km. A random sample
of 200 tires is tested . What is the problability of the mean life of this sample being between 109,000 and 111,000 km?

asked by Carlos
  1. Z = (score-mean)/SEm

    SEm = SD/√n

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z scores.

    posted by PsyDAG

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